Ah, so she's made a slave.
Eh, a gladiator, a slave, same thing.
You really should have watched this
before watching "Cherry Bomb". AJ's an employee of the cherry ranch, not a slave.
You wanna kick mathematics? You're subtraction, I'm addition.
You wanna kick mathematics? You're subtraction, I'm addition.
Alternately, since magic in the series likely runs on emotion (hence why love,
in its various forms, is so damn powerful), there's probably some way to exactly determine one's mental state. They would know if Luna's apology was sincere.
edited 10th Aug '12 10:02:12 PM by Blueeyedrat
"I've come to the conclusion that this is a very stupid idea."
@Roy: Nope, she couldn't bear the thought of letting everypony down. I've been down that path before, so I know AJ's feel.
Twitchy ear means bad things.
So now we have to worry about Twilight Sense too?
Life is simple: it has no nontrivial normal subgroups.
@Mio: I actually kind of find it interesting that so many people make the assumption "the ponies are really just as nasty as humans, only we don't see it because it's a kid's show" rather than assuming that Equestria really is as much of a sugar bowl as it looks and everything in the show is how the place actually is.
Applejack better be in some really dire situation to top that
Does being enslaved with a bomb strapped to her count?
Life is simple: it has no nontrivial normal subgroups.
It's not that she lost. It's that she broke her promise to bring home money. She never goes back on a promise, so she tried to earn the money by working in Dodge Junction before she would even consider showing her face in Ponyville again.
Wait, THAT's the reason why she didn't return? This got to be kidding me.
I have totally been in AJ's situation, and actually responded the same way she did.
You wanna kick mathematics? You're subtraction, I'm addition.
Wait, you actually thought AJ was a slave? I thought you were joking at first. And yes, the actual ending is pretty much copied verbatim in
Fi W except with an added bomb.
Life is simple: it has no nontrivial normal subgroups.